Base | Representation |
---|---|
bin | 11000101011101001… |
… | …01101110110101101 |
3 | 1021012111011201100111 |
4 | 30111310231312231 |
5 | 204114231331413 |
6 | 10030515500021 |
7 | 646242001435 |
oct | 142564556655 |
9 | 37174151314 |
10 | 13251042733 |
11 | 568a960595 |
12 | 26998b7611 |
13 | 13323babb6 |
14 | 8d9c372c5 |
15 | 5284ded3d |
hex | 315d2ddad |
13251042733 has 2 divisors, whose sum is σ = 13251042734. Its totient is φ = 13251042732.
The previous prime is 13251042661. The next prime is 13251042773. The reversal of 13251042733 is 33724015231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11646078889 + 1604963844 = 107917^2 + 40062^2 .
It is an emirp because it is prime and its reverse (33724015231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13251042733 - 213 = 13251034541 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13251042695 and 13251042704.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13251042773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625521366 + 6625521367.
It is an arithmetic number, because the mean of its divisors is an integer number (6625521367).
Almost surely, 213251042733 is an apocalyptic number.
It is an amenable number.
13251042733 is a deficient number, since it is larger than the sum of its proper divisors (1).
13251042733 is an equidigital number, since it uses as much as digits as its factorization.
13251042733 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 13251042733 its reverse (33724015231), we get a palindrome (46975057964).
The spelling of 13251042733 in words is "thirteen billion, two hundred fifty-one million, forty-two thousand, seven hundred thirty-three".
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