Base | Representation |
---|---|
bin | 1100000011010100001111… |
… | …1100111000111010101011 |
3 | 1201220210102221001201211020 |
4 | 3000311003330320322223 |
5 | 3214101240210042103 |
6 | 44103251112103523 |
7 | 2535234650531553 |
oct | 300650374707253 |
9 | 51823387051736 |
10 | 13251114143403 |
11 | 4249847529414 |
12 | 15a01a3394ba3 |
13 | 75176180a756 |
14 | 33b5007b8163 |
15 | 17ea5a1cc753 |
hex | c0d43f38eab |
13251114143403 has 32 divisors (see below), whose sum is σ = 17875770783552. Its totient is φ = 8730949516800.
The previous prime is 13251114143303. The next prime is 13251114143507. The reversal of 13251114143403 is 30434141115231.
It is a happy number.
It is not a de Polignac number, because 13251114143403 - 226 = 13251047034539 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13251114143203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 120694113 + ... + 120803853.
It is an arithmetic number, because the mean of its divisors is an integer number (558617836986).
Almost surely, 213251114143403 is an apocalyptic number.
13251114143403 is a deficient number, since it is larger than the sum of its proper divisors (4624656640149).
13251114143403 is a wasteful number, since it uses less digits than its factorization.
13251114143403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 111295.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 13251114143403 its reverse (30434141115231), we get a palindrome (43685255258634).
The spelling of 13251114143403 in words is "thirteen trillion, two hundred fifty-one billion, one hundred fourteen million, one hundred forty-three thousand, four hundred three".
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