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132512412523261 is a prime number
BaseRepresentation
bin11110001000010011110011…
…010001101101101011111101
3122101012001200212102100212011
4132020103303101231223331
5114332040410101221021
61145455210101411221
736624464053613521
oct3610236321555375
9571161625370764
10132512412523261
113924a2203069a1
1212a41962a09b11
1358c2b36706634
1424a18c6593d81
15104be42c63de1
hex7884f346dafd

132512412523261 has 2 divisors, whose sum is σ = 132512412523262. Its totient is φ = 132512412523260.

The previous prime is 132512412523217. The next prime is 132512412523277. The reversal of 132512412523261 is 162325214215231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132408402403225 + 104010120036 = 11506885^2 + 322506^2 .

It is a cyclic number.

It is not a de Polignac number, because 132512412523261 - 229 = 132511875652349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132512412523201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66256206261630 + 66256206261631.

It is an arithmetic number, because the mean of its divisors is an integer number (66256206261631).

Almost surely, 2132512412523261 is an apocalyptic number.

It is an amenable number.

132512412523261 is a deficient number, since it is larger than the sum of its proper divisors (1).

132512412523261 is an equidigital number, since it uses as much as digits as its factorization.

132512412523261 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 172800, while the sum is 40.

Adding to 132512412523261 its reverse (162325214215231), we get a palindrome (294837626738492).

The spelling of 132512412523261 in words is "one hundred thirty-two trillion, five hundred twelve billion, four hundred twelve million, five hundred twenty-three thousand, two hundred sixty-one".