Base | Representation |
---|---|
bin | 1100000011010101001000… |
… | …0010100101001111101101 |
3 | 1201220211001101211202001102 |
4 | 3000311102002211033231 |
5 | 3214102231213013332 |
6 | 44103330354252445 |
7 | 2535243550630565 |
oct | 300652202451755 |
9 | 51824041752042 |
10 | 13251350516717 |
11 | 42499589a5165 |
12 | 15a024a587125 |
13 | 75179b78b911 |
14 | 33b523d47da5 |
15 | 17ea70d1e062 |
hex | c0d520a53ed |
13251350516717 has 2 divisors, whose sum is σ = 13251350516718. Its totient is φ = 13251350516716.
The previous prime is 13251350516653. The next prime is 13251350516779. The reversal of 13251350516717 is 71761505315231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11753727713641 + 1497622803076 = 3428371^2 + 1223774^2 .
It is a cyclic number.
It is not a de Polignac number, because 13251350516717 - 26 = 13251350516653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13251350512717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625675258358 + 6625675258359.
It is an arithmetic number, because the mean of its divisors is an integer number (6625675258359).
Almost surely, 213251350516717 is an apocalyptic number.
It is an amenable number.
13251350516717 is a deficient number, since it is larger than the sum of its proper divisors (1).
13251350516717 is an equidigital number, since it uses as much as digits as its factorization.
13251350516717 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 661500, while the sum is 47.
The spelling of 13251350516717 in words is "thirteen trillion, two hundred fifty-one billion, three hundred fifty million, five hundred sixteen thousand, seven hundred seventeen".
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