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13251394339 = 22359423293
BaseRepresentation
bin11000101011101100…
…00011101100100011
31021012111211120122221
430111312003230203
5204114324104324
610030531211511
7646244664511
oct142566035443
937174746587
1013251394339
115690080777
122699a46b97
1313324b1c51
148d9cc94b1
1552855e0e4
hex315d83b23

13251394339 has 4 divisors (see below), whose sum is σ = 13310817856. Its totient is φ = 13191970824.

The previous prime is 13251394337. The next prime is 13251394369. The reversal of 13251394339 is 93349315231.

13251394339 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13251394339 - 21 = 13251394337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13251394295 and 13251394304.

It is not an unprimeable number, because it can be changed into a prime (13251394337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29711424 + ... + 29711869.

It is an arithmetic number, because the mean of its divisors is an integer number (3327704464).

Almost surely, 213251394339 is an apocalyptic number.

13251394339 is a deficient number, since it is larger than the sum of its proper divisors (59423517).

13251394339 is an equidigital number, since it uses as much as digits as its factorization.

13251394339 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59423516.

The product of its digits is 262440, while the sum is 43.

The spelling of 13251394339 in words is "thirteen billion, two hundred fifty-one million, three hundred ninety-four thousand, three hundred thirty-nine".

Divisors: 1 223 59423293 13251394339