132520000001 has 4 divisors (see below), whose sum is σ = 133023878592. Its totient is φ = 132016121412.

The previous prime is 132519999991. The next prime is 132520000003. The reversal of 132520000001 is 100000025231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100000025231 = 14669 ⋅6817099.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132520000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132520000003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251938901 + ... + 251939426.

It is an arithmetic number, because the mean of its divisors is an integer number (33255969648).

Almost surely, 2^132520000001 is an apocalyptic number.

It is an amenable number.

132520000001 is a deficient number, since it is larger than the sum of its proper divisors (503878591).

132520000001 is an equidigital number, since it uses as much as digits as its factorization.

132520000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 503878590.

The product of its (nonzero) digits is 60, while the sum is 14.

Adding to 132520000001 its reverse (100000025231), we get a palindrome (232520025232).

The spelling of 132520000001 in words is "one hundred thirty-two billion, five hundred twenty million, one", and thus it is an aban number.