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1325214047 is a prime number
BaseRepresentation
bin100111011111101…
…0010100101011111
310102100121211220202
41032333102211133
510203223322142
6335255534115
744561063543
oct11677224537
93370554822
101325214047
11620059a23
1230b98a33b
13181725731
14c8005a23
157b521032
hex4efd295f

1325214047 has 2 divisors, whose sum is σ = 1325214048. Its totient is φ = 1325214046.

The previous prime is 1325214029. The next prime is 1325214061. The reversal of 1325214047 is 7404125231.

It is a strong prime.

It is an emirp because it is prime and its reverse (7404125231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1325214047 - 26 = 1325213983 is a prime.

It is a super-2 number, since 2×13252140472 = 3512384540732236418, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1325214017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662607023 + 662607024.

It is an arithmetic number, because the mean of its divisors is an integer number (662607024).

Almost surely, 21325214047 is an apocalyptic number.

1325214047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325214047 is an equidigital number, since it uses as much as digits as its factorization.

1325214047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 29.

The square root of 1325214047 is about 36403.4894893333. The cubic root of 1325214047 is about 1098.4037583219.

Adding to 1325214047 its reverse (7404125231), we get a palindrome (8729339278).

The spelling of 1325214047 in words is "one billion, three hundred twenty-five million, two hundred fourteen thousand, forty-seven".