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13252305131341 is a prime number
BaseRepresentation
bin1100000011011000101011…
…1100001001011101001101
31201220220111221010012010121
43000312022330021131031
53214111210103200331
644104005215104541
72535306322003603
oct300661274113515
951826457105117
1013252305131341
11424a2a883a271
1215a0476212151
137518c1497c43
1433b5b4a3d873
1517eac9a37c11
hexc0d8af0974d

13252305131341 has 2 divisors, whose sum is σ = 13252305131342. Its totient is φ = 13252305131340.

The previous prime is 13252305131333. The next prime is 13252305131347. The reversal of 13252305131341 is 14313150325231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6654573485316 + 6597731646025 = 2579646^2 + 2568605^2 .

It is a cyclic number.

It is not a de Polignac number, because 13252305131341 - 23 = 13252305131333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13252305131297 and 13252305131306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13252305131347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626152565670 + 6626152565671.

It is an arithmetic number, because the mean of its divisors is an integer number (6626152565671).

Almost surely, 213252305131341 is an apocalyptic number.

It is an amenable number.

13252305131341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13252305131341 is an equidigital number, since it uses as much as digits as its factorization.

13252305131341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 13252305131341 its reverse (14313150325231), we get a palindrome (27565455456572).

The spelling of 13252305131341 in words is "thirteen trillion, two hundred fifty-two billion, three hundred five million, one hundred thirty-one thousand, three hundred forty-one".