Base | Representation |
---|---|
bin | 11000101011110011… |
… | …00101101100101001 |
3 | 1021012120120121111012 |
4 | 30111321211230221 |
5 | 204120043220131 |
6 | 10031003113305 |
7 | 646255601402 |
oct | 142571455451 |
9 | 37176517435 |
10 | 13252320041 |
11 | 5690653214 |
12 | 269a212835 |
13 | 13327473bc |
14 | 8da08a9a9 |
15 | 52869352b |
hex | 315e65b29 |
13252320041 has 4 divisors (see below), whose sum is σ = 13267363284. Its totient is φ = 13237276800.
The previous prime is 13252320019. The next prime is 13252320043. The reversal of 13252320041 is 14002325231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1065043225 + 12187276816 = 32635^2 + 110396^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13252320041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13252319989 and 13252320016.
It is not an unprimeable number, because it can be changed into a prime (13252320043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7520300 + ... + 7522061.
It is an arithmetic number, because the mean of its divisors is an integer number (3316840821).
Almost surely, 213252320041 is an apocalyptic number.
It is an amenable number.
13252320041 is a deficient number, since it is larger than the sum of its proper divisors (15043243).
13252320041 is an equidigital number, since it uses as much as digits as its factorization.
13252320041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15043242.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 13252320041 its reverse (14002325231), we get a palindrome (27254645272).
The spelling of 13252320041 in words is "thirteen billion, two hundred fifty-two million, three hundred twenty thousand, forty-one".
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