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132523641115 = 531854991233
BaseRepresentation
bin111101101101100000…
…1100100100100011011
3110200001210121111102021
41323123001210210123
54132402023003430
6140514105315311
712401026235425
oct1733301444433
9420053544367
10132523641115
1151226160048
1221825a95b37
13c65c9907b8
1465b2711815
1536a96ae07a
hex1edb06491b

132523641115 has 8 divisors (see below), whose sum is σ = 164158316928. Its totient is φ = 102598947840.

The previous prime is 132523641113. The next prime is 132523641121. The reversal of 132523641115 is 511146325231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132523641115 - 21 = 132523641113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132523641113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 427495462 + ... + 427495771.

It is an arithmetic number, because the mean of its divisors is an integer number (20519789616).

Almost surely, 2132523641115 is an apocalyptic number.

132523641115 is a deficient number, since it is larger than the sum of its proper divisors (31634675813).

132523641115 is an equidigital number, since it uses as much as digits as its factorization.

132523641115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 854991269.

The product of its digits is 21600, while the sum is 34.

Adding to 132523641115 its reverse (511146325231), we get a palindrome (643669966346).

The spelling of 132523641115 in words is "one hundred thirty-two billion, five hundred twenty-three million, six hundred forty-one thousand, one hundred fifteen".

Divisors: 1 5 31 155 854991233 4274956165 26504728223 132523641115