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13252467644417 is a prime number
BaseRepresentation
bin1100000011011001010010…
…1000000101100000000001
31201220220221020220201011102
43000312110220011200001
53214112023204110132
644104033302224145
72535313334230631
oct300662450054001
951826836821142
1013252467644417
11424a3815487a1
1215a0500725055
13751919058521
1433b5cc4646c1
1517ead8e39c62
hexc0d94a05801

13252467644417 has 2 divisors, whose sum is σ = 13252467644418. Its totient is φ = 13252467644416.

The previous prime is 13252467644389. The next prime is 13252467644473. The reversal of 13252467644417 is 71444676425231.

It is an a-pointer prime, because the next prime (13252467644473) can be obtained adding 13252467644417 to its sum of digits (56).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12264032016016 + 988435628401 = 3502004^2 + 994201^2 .

It is a cyclic number.

It is not a de Polignac number, because 13252467644417 - 28 = 13252467644161 is a prime.

It is a super-5 number, since 5×132524676444175 (a number of 67 digits) contains 55555 as substring.

It is not a weakly prime, because it can be changed into another prime (13252467644497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626233822208 + 6626233822209.

It is an arithmetic number, because the mean of its divisors is an integer number (6626233822209).

Almost surely, 213252467644417 is an apocalyptic number.

It is an amenable number.

13252467644417 is a deficient number, since it is larger than the sum of its proper divisors (1).

13252467644417 is an equidigital number, since it uses as much as digits as its factorization.

13252467644417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27095040, while the sum is 56.

The spelling of 13252467644417 in words is "thirteen trillion, two hundred fifty-two billion, four hundred sixty-seven million, six hundred forty-four thousand, four hundred seventeen".