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132530430000 = 243546172421
BaseRepresentation
bin111101101101101101…
…1011110000000110000
3110200002021101102000110
41323123123132000300
54132410242230000
6140514511021320
712401141032203
oct1733333360060
9420067342013
10132530430000
1151229a776a1
122182820a840
13c6611c98a7
1465b359b93a
1536aa0a0850
hex1edb6de030

132530430000 has 200 divisors, whose sum is σ = 434845442416. Its totient is φ = 34761600000.

The previous prime is 132530429987. The next prime is 132530430059. The reversal of 132530430000 is 34035231.

It is a tau number, because it is divible by the number of its divisors (200).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1793790 + ... + 1866210.

Almost surely, 2132530430000 is an apocalyptic number.

132530430000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132530430000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217422721208).

132530430000 is an abundant number, since it is smaller than the sum of its proper divisors (302315012416).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132530430000 is an equidigital number, since it uses as much as digits as its factorization.

132530430000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72513 (or 72492 counting only the distinct ones).

The product of its (nonzero) digits is 1080, while the sum is 21.

Adding to 132530430000 its reverse (34035231), we get a palindrome (132564465231).

The spelling of 132530430000 in words is "one hundred thirty-two billion, five hundred thirty million, four hundred thirty thousand".