Base | Representation |
---|---|
bin | 1100000011011011011101… |
… | …1010010010100100100101 |
3 | 1201220222102221000221202211 |
4 | 3000312313122102210211 |
5 | 3214114222103334001 |
6 | 44104211230403421 |
7 | 2535333651515035 |
oct | 300666732224445 |
9 | 51828387027684 |
10 | 13253051230501 |
11 | 424a650a05645 |
12 | 15a0644060571 |
13 | 7519acc28034 |
14 | 33b645b778c5 |
15 | 17eb202b4351 |
hex | c0db7692925 |
13253051230501 has 16 divisors (see below), whose sum is σ = 14518053662400. Its totient is φ = 12042073861888.
The previous prime is 13253051230469. The next prime is 13253051230589. The reversal of 13253051230501 is 10503215035231.
It is not a de Polignac number, because 13253051230501 - 25 = 13253051230469 is a prime.
It is a super-2 number, since 2×132530512305012 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13253051230201) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3293646 + ... + 6111808.
It is an arithmetic number, because the mean of its divisors is an integer number (907378353900).
Almost surely, 213253051230501 is an apocalyptic number.
It is an amenable number.
13253051230501 is a deficient number, since it is larger than the sum of its proper divisors (1265002431899).
13253051230501 is a wasteful number, since it uses less digits than its factorization.
13253051230501 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2827748.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 13253051230501 its reverse (10503215035231), we get a palindrome (23756266265732).
The spelling of 13253051230501 in words is "thirteen trillion, two hundred fifty-three billion, fifty-one million, two hundred thirty thousand, five hundred one".
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