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1325333502443 is a prime number
BaseRepresentation
bin10011010010010100000…
…010000101100111101011
311200200220202210201101102
4103102110002011213223
5133203240334034233
62452503320312015
7164515666616156
oct23222402054753
94620822721342
101325333502443
11471086235575
12194a3761260b
1397c9475b982
1448209d46c9d
152471d0231e8
hex134940859eb

1325333502443 has 2 divisors, whose sum is σ = 1325333502444. Its totient is φ = 1325333502442.

The previous prime is 1325333502391. The next prime is 1325333502481. The reversal of 1325333502443 is 3442053335231.

It is an a-pointer prime, because the next prime (1325333502481) can be obtained adding 1325333502443 to its sum of digits (38).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1325333502443 - 210 = 1325333501419 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1325333502397 and 1325333502406.

It is not a weakly prime, because it can be changed into another prime (1325333702443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662666751221 + 662666751222.

It is an arithmetic number, because the mean of its divisors is an integer number (662666751222).

Almost surely, 21325333502443 is an apocalyptic number.

1325333502443 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325333502443 is an equidigital number, since it uses as much as digits as its factorization.

1325333502443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 38.

Adding to 1325333502443 its reverse (3442053335231), we get a palindrome (4767386837674).

The spelling of 1325333502443 in words is "one trillion, three hundred twenty-five billion, three hundred thirty-three million, five hundred two thousand, four hundred forty-three".