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13253403 = 38215381
BaseRepresentation
bin110010100011…
…101100011011
3220221100020210
4302203230123
511343102103
61152022203
7220436442
oct62435433
926840223
1013253403
117532529
124531963
132990667
141a8dd59
15126be03
hexca3b1b

13253403 has 8 divisors (see below), whose sum is σ = 17696016. Its totient is φ = 8823200.

The previous prime is 13253381. The next prime is 13253407. The reversal of 13253403 is 30435231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13253403 - 28 = 13253147 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13253403.

It is not an unprimeable number, because it can be changed into a prime (13253407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 228 + ... + 5153.

It is an arithmetic number, because the mean of its divisors is an integer number (2212002).

Almost surely, 213253403 is an apocalyptic number.

13253403 is a deficient number, since it is larger than the sum of its proper divisors (4442613).

13253403 is an equidigital number, since it uses as much as digits as its factorization.

13253403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6205.

The product of its (nonzero) digits is 1080, while the sum is 21.

The square root of 13253403 is about 3640.5223526302. The cubic root of 13253403 is about 236.6514308339.

Adding to 13253403 its reverse (30435231), we get a palindrome (43688634).

It can be divided in two parts, 132 and 53403, that added together give a palindrome (53535).

The spelling of 13253403 in words is "thirteen million, two hundred fifty-three thousand, four hundred three".

Divisors: 1 3 821 2463 5381 16143 4417801 13253403