Base | Representation |
---|---|
bin | 10011010010010100100… |
… | …010111101111001010011 |
3 | 11200200221101000121120210 |
4 | 103102110202331321103 |
5 | 133203300040342210 |
6 | 2452504225135203 |
7 | 164516133104604 |
oct | 23222442757123 |
9 | 4620841017523 |
10 | 1325342121555 |
11 | 471090092201 |
12 | 194a3a48a503 |
13 | 97c96488b3a |
14 | 4820b14bdab |
15 | 2471db76e20 |
hex | 134948bde53 |
1325342121555 has 8 divisors (see below), whose sum is σ = 2120547394512. Its totient is φ = 706849131488.
The previous prime is 1325342121547. The next prime is 1325342121581. The reversal of 1325342121555 is 5551212435231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1325342121555 - 23 = 1325342121547 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44178070704 + ... + 44178070733.
It is an arithmetic number, because the mean of its divisors is an integer number (265068424314).
Almost surely, 21325342121555 is an apocalyptic number.
1325342121555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1325342121555 is a deficient number, since it is larger than the sum of its proper divisors (795205272957).
1325342121555 is an equidigital number, since it uses as much as digits as its factorization.
1325342121555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88356141445.
The product of its digits is 180000, while the sum is 39.
Adding to 1325342121555 its reverse (5551212435231), we get a palindrome (6876554556786).
The spelling of 1325342121555 in words is "one trillion, three hundred twenty-five billion, three hundred forty-two million, one hundred twenty-one thousand, five hundred fifty-five".
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