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13253505214349 is a prime number
BaseRepresentation
bin1100000011011101001001…
…1110000110011110001101
31201221000121120021201112102
43000313102132012132031
53214121134313324344
644104324245044445
72535351133356101
oct300672236063615
951830546251472
1013253505214349
11424a8641a2404
1215a07500b6725
13751a52cbb12a
1433b68a191901
1517eb4a08ce4e
hexc0dd278678d

13253505214349 has 2 divisors, whose sum is σ = 13253505214350. Its totient is φ = 13253505214348.

The previous prime is 13253505214297. The next prime is 13253505214363. The reversal of 13253505214349 is 94341250535231.

13253505214349 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12764649745225 + 488855469124 = 3572765^2 + 699182^2 .

It is a cyclic number.

It is not a de Polignac number, because 13253505214349 - 228 = 13253236778893 is a prime.

It is a super-2 number, since 2×132535052143492 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13253505214049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626752607174 + 6626752607175.

It is an arithmetic number, because the mean of its divisors is an integer number (6626752607175).

Almost surely, 213253505214349 is an apocalyptic number.

It is an amenable number.

13253505214349 is a deficient number, since it is larger than the sum of its proper divisors (1).

13253505214349 is an equidigital number, since it uses as much as digits as its factorization.

13253505214349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 47.

The spelling of 13253505214349 in words is "thirteen trillion, two hundred fifty-three billion, five hundred five million, two hundred fourteen thousand, three hundred forty-nine".