Base | Representation |
---|---|
bin | 11000101011111111… |
… | …01110001101000011 |
3 | 1021012200121021211212 |
4 | 30111333232031003 |
5 | 204121001141442 |
6 | 10031101400335 |
7 | 646305345524 |
oct | 142577561503 |
9 | 37180537755 |
10 | 13253927747 |
11 | 56915510a5 |
12 | 269a8690ab |
13 | 1332b8b0c8 |
14 | 8da38884b |
15 | 5288aea82 |
hex | 315fee343 |
13253927747 has 2 divisors, whose sum is σ = 13253927748. Its totient is φ = 13253927746.
The previous prime is 13253927647. The next prime is 13253927749. The reversal of 13253927747 is 74772935231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13253927747 - 210 = 13253926723 is a prime.
Together with 13253927749, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13253927695 and 13253927704.
It is not a weakly prime, because it can be changed into another prime (13253927749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626963873 + 6626963874.
It is an arithmetic number, because the mean of its divisors is an integer number (6626963874).
Almost surely, 213253927747 is an apocalyptic number.
13253927747 is a deficient number, since it is larger than the sum of its proper divisors (1).
13253927747 is an equidigital number, since it uses as much as digits as its factorization.
13253927747 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2222640, while the sum is 50.
The spelling of 13253927747 in words is "thirteen billion, two hundred fifty-three million, nine hundred twenty-seven thousand, seven hundred forty-seven".
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