Base | Representation |
---|---|
bin | 11000101011111111… |
… | …11111111111111101 |
3 | 1021012200201222211111 |
4 | 30111333333333331 |
5 | 204121011010022 |
6 | 10031103122021 |
7 | 646306101163 |
oct | 142577777775 |
9 | 37180658744 |
10 | 13254000637 |
11 | 56915a0939 |
12 | 269a8a3311 |
13 | 1332bb5337 |
14 | 8da3a7233 |
15 | 5288c6477 |
hex | 315fffffd |
13254000637 has 2 divisors, whose sum is σ = 13254000638. Its totient is φ = 13254000636.
The previous prime is 13254000541. The next prime is 13254000647. The reversal of 13254000637 is 73600045231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13253995876 + 4761 = 115126^2 + 69^2 .
It is an emirp because it is prime and its reverse (73600045231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13254000637 - 27 = 13254000509 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13254000599 and 13254000608.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13254000647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627000318 + 6627000319.
It is an arithmetic number, because the mean of its divisors is an integer number (6627000319).
Almost surely, 213254000637 is an apocalyptic number.
It is an amenable number.
13254000637 is a deficient number, since it is larger than the sum of its proper divisors (1).
13254000637 is an equidigital number, since it uses as much as digits as its factorization.
13254000637 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 13254000637 its reverse (73600045231), we get a palindrome (86854045868).
The spelling of 13254000637 in words is "thirteen billion, two hundred fifty-four million, six hundred thirty-seven", and thus it is an aban number.
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