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13254000637 is a prime number
BaseRepresentation
bin11000101011111111…
…11111111111111101
31021012200201222211111
430111333333333331
5204121011010022
610031103122021
7646306101163
oct142577777775
937180658744
1013254000637
1156915a0939
12269a8a3311
131332bb5337
148da3a7233
155288c6477
hex315fffffd

13254000637 has 2 divisors, whose sum is σ = 13254000638. Its totient is φ = 13254000636.

The previous prime is 13254000541. The next prime is 13254000647. The reversal of 13254000637 is 73600045231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13253995876 + 4761 = 115126^2 + 69^2 .

It is an emirp because it is prime and its reverse (73600045231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13254000637 - 27 = 13254000509 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13254000599 and 13254000608.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13254000647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627000318 + 6627000319.

It is an arithmetic number, because the mean of its divisors is an integer number (6627000319).

Almost surely, 213254000637 is an apocalyptic number.

It is an amenable number.

13254000637 is a deficient number, since it is larger than the sum of its proper divisors (1).

13254000637 is an equidigital number, since it uses as much as digits as its factorization.

13254000637 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 31.

Adding to 13254000637 its reverse (73600045231), we get a palindrome (86854045868).

The spelling of 13254000637 in words is "thirteen billion, two hundred fifty-four million, six hundred thirty-seven", and thus it is an aban number.