Base | Representation |
---|---|
bin | 11110001000101101100010… |
… | …001000101110000000000011 |
3 | 122101021201000102121101212110 |
4 | 132020231202020232000003 |
5 | 114333014001303140003 |
6 | 1145520015502230403 |
7 | 36626462542414536 |
oct | 3610554210560003 |
9 | 571251012541773 |
10 | 132540042240003 |
11 | 3925aa09595042 |
12 | 12a47193b85403 |
13 | 58c561a9b8b58 |
14 | 24a2d87cb6a1d |
15 | 104ca0d736a03 |
hex | 788b6222e003 |
132540042240003 has 8 divisors (see below), whose sum is σ = 180829825071808. Its totient is φ = 86305143784104.
The previous prime is 132540042239959. The next prime is 132540042240043. The reversal of 132540042240003 is 300042240045231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132540042240003 - 212 = 132540042235907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132540042240043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 513721093825 + ... + 513721094082.
It is an arithmetic number, because the mean of its divisors is an integer number (22603728133976).
Almost surely, 2132540042240003 is an apocalyptic number.
132540042240003 is a deficient number, since it is larger than the sum of its proper divisors (48289782831805).
132540042240003 is a wasteful number, since it uses less digits than its factorization.
132540042240003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1027442187953.
The product of its (nonzero) digits is 23040, while the sum is 30.
Adding to 132540042240003 its reverse (300042240045231), we get a palindrome (432582282285234).
The spelling of 132540042240003 in words is "one hundred thirty-two trillion, five hundred forty billion, forty-two million, two hundred forty thousand, three".
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