Base | Representation |
---|---|
bin | 10011010010011000001… |
… | …100001010110101010111 |
3 | 11200201002122001110200020 |
4 | 103102120030022311113 |
5 | 133203411213112403 |
6 | 2452514251320223 |
7 | 164520504526605 |
oct | 23223014126527 |
9 | 4621078043606 |
10 | 1325403254103 |
11 | 471111646a75 |
12 | 194a56a50073 |
13 | 97ca6041446 |
14 | 48215302875 |
15 | 24724200453 |
hex | 1349830ad57 |
1325403254103 has 8 divisors (see below), whose sum is σ = 1767238905216. Its totient is φ = 883584886200.
The previous prime is 1325403254093. The next prime is 1325403254137. The reversal of 1325403254103 is 3014523045231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1325403254103 - 28 = 1325403253847 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1325403254003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4140793 + ... + 4449378.
It is an arithmetic number, because the mean of its divisors is an integer number (220904863152).
Almost surely, 21325403254103 is an apocalyptic number.
1325403254103 is a deficient number, since it is larger than the sum of its proper divisors (441835651113).
1325403254103 is an equidigital number, since it uses as much as digits as its factorization.
1325403254103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8641605.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 1325403254103 its reverse (3014523045231), we get a palindrome (4339926299334).
The spelling of 1325403254103 in words is "one trillion, three hundred twenty-five billion, four hundred three million, two hundred fifty-four thousand, one hundred three".
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