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1325403254111 = 3196959440959
BaseRepresentation
bin10011010010011000001…
…100001010110101011111
311200201002122001110200112
4103102120030022311133
5133203411213112421
62452514251320235
7164520504526616
oct23223014126537
94621078043615
101325403254111
11471111646a82
12194a56a5007b
1397ca6041451
144821530287d
152472420045b
hex1349830ad5f

1325403254111 has 8 divisors (see below), whose sum is σ = 1368175411200. Its totient is φ = 1282632172920.

The previous prime is 1325403254093. The next prime is 1325403254137. The reversal of 1325403254111 is 1114523045231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1325403254111 - 218 = 1325402991967 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1325403254411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2785250 + ... + 3226208.

It is an arithmetic number, because the mean of its divisors is an integer number (171021926400).

Almost surely, 21325403254111 is an apocalyptic number.

1325403254111 is a deficient number, since it is larger than the sum of its proper divisors (42772157089).

1325403254111 is an equidigital number, since it uses as much as digits as its factorization.

1325403254111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 537949.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 1325403254111 its reverse (1114523045231), we get a palindrome (2439926299342).

The spelling of 1325403254111 in words is "one trillion, three hundred twenty-five billion, four hundred three million, two hundred fifty-four thousand, one hundred eleven".

Divisors: 1 31 96959 440959 3005729 13669729 42754943681 1325403254111