Base | Representation |
---|---|
bin | 100111100000000… |
… | …0000111110011001 |
3 | 10102100222111120011 |
4 | 1033000000332121 |
5 | 10203300412212 |
6 | 335304001521 |
7 | 44562514525 |
oct | 11700007631 |
9 | 3370874504 |
10 | 1325404057 |
11 | 62017975a |
12 | 30ba602a1 |
13 | 181791073 |
14 | c8054d85 |
15 | 7b55c4a7 |
hex | 4f000f99 |
1325404057 has 2 divisors, whose sum is σ = 1325404058. Its totient is φ = 1325404056.
The previous prime is 1325404037. The next prime is 1325404097. The reversal of 1325404057 is 7504045231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 935381056 + 390023001 = 30584^2 + 19749^2 .
It is a cyclic number.
It is not a de Polignac number, because 1325404057 - 211 = 1325402009 is a prime.
It is not a weakly prime, because it can be changed into another prime (1325404037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662702028 + 662702029.
It is an arithmetic number, because the mean of its divisors is an integer number (662702029).
Almost surely, 21325404057 is an apocalyptic number.
It is an amenable number.
1325404057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325404057 is an equidigital number, since it uses as much as digits as its factorization.
1325404057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16800, while the sum is 31.
The square root of 1325404057 is about 36406.0991730781. The cubic root of 1325404057 is about 1098.4562524138.
Adding to 1325404057 its reverse (7504045231), we get a palindrome (8829449288).
The spelling of 1325404057 in words is "one billion, three hundred twenty-five million, four hundred four thousand, fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •