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13254140342042 = 26627070171021
BaseRepresentation
bin1100000011011111100001…
…0100111010111100011010
31201221002020211101112221022
43000313320110322330122
53214123434411421132
644104511254042442
72535402645021245
oct300677024727432
951832224345838
1013254140342042
11425005a763226
1215a08a8949422
13751b24765932
1433b70a68025c
1517eb85be8e12
hexc0df853af1a

13254140342042 has 4 divisors (see below), whose sum is σ = 19881210513066. Its totient is φ = 6627070171020.

The previous prime is 13254140342011. The next prime is 13254140342083. The reversal of 13254140342042 is 24024304145231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8831779492561 + 4422360849481 = 2971831^2 + 2102941^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13254140341993 and 13254140342011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3313535085509 + ... + 3313535085512.

Almost surely, 213254140342042 is an apocalyptic number.

13254140342042 is a deficient number, since it is larger than the sum of its proper divisors (6627070171024).

13254140342042 is an equidigital number, since it uses as much as digits as its factorization.

13254140342042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6627070171023.

The product of its (nonzero) digits is 92160, while the sum is 35.

Adding to 13254140342042 its reverse (24024304145231), we get a palindrome (37278444487273).

The spelling of 13254140342042 in words is "thirteen trillion, two hundred fifty-four billion, one hundred forty million, three hundred forty-two thousand, forty-two".

Divisors: 1 2 6627070171021 13254140342042