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13254331103014 = 215742211245551
BaseRepresentation
bin1100000011100000001110…
…1100100111011100100110
31201221002202010100012210111
43000320003230213130212
53214124332230244024
644104542230443234
72535410452325551
oct300700354473446
951832663305714
1013254331103014
114250148405821
1215a094080351a
13751b55136851
1433b727b39698
1517eb9782aa94
hexc0e03b27726

13254331103014 has 8 divisors (see below), whose sum is σ = 20008130391648. Its totient is φ = 6584954305800.

The previous prime is 13254331103003. The next prime is 13254331103033. The reversal of 13254331103014 is 41030113345231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×132543311030143 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21105622462 + ... + 21105623089.

It is an arithmetic number, because the mean of its divisors is an integer number (2501016298956).

Almost surely, 213254331103014 is an apocalyptic number.

13254331103014 is a deficient number, since it is larger than the sum of its proper divisors (6753799288634).

13254331103014 is a wasteful number, since it uses less digits than its factorization.

13254331103014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42211245710.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 13254331103014 its reverse (41030113345231), we get a palindrome (54284444448245).

The spelling of 13254331103014 in words is "thirteen trillion, two hundred fifty-four billion, three hundred thirty-one million, one hundred three thousand, fourteen".

Divisors: 1 2 157 314 42211245551 84422491102 6627165551507 13254331103014