Base | Representation |
---|---|
bin | 111101101110000110… |
… | …0101011110011010110 |
3 | 110200010011122212121100 |
4 | 1323130030223303112 |
5 | 4132422043102132 |
6 | 140520051330530 |
7 | 12401355505056 |
oct | 1733414536326 |
9 | 420104585540 |
10 | 132543331542 |
11 | 51236289826 |
12 | 218305b0a46 |
13 | c663a9603b |
14 | 65b5199566 |
15 | 36ab29d37c |
hex | 1edc32bcd6 |
132543331542 has 48 divisors (see below), whose sum is σ = 302337322560. Its totient is φ = 41849487216.
The previous prime is 132543331541. The next prime is 132543331549. The reversal of 132543331542 is 245133345231.
132543331542 is a `hidden beast` number, since 1 + 3 + 2 + 54 + 33 + 31 + 542 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 132543331497 and 132543331506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132543331541) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2588553 + ... + 2639259.
It is an arithmetic number, because the mean of its divisors is an integer number (6298694220).
Almost surely, 2132543331542 is an apocalyptic number.
132543331542 is an abundant number, since it is smaller than the sum of its proper divisors (169793991018).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132543331542 is a wasteful number, since it uses less digits than its factorization.
132543331542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58377 (or 58374 counting only the distinct ones).
The product of its digits is 129600, while the sum is 36.
Adding to 132543331542 its reverse (245133345231), we get a palindrome (377676676773).
The spelling of 132543331542 in words is "one hundred thirty-two billion, five hundred forty-three million, three hundred thirty-one thousand, five hundred forty-two".
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