Base | Representation |
---|---|
bin | 11000101100000010… |
… | …10011100110001011 |
3 | 1021012201101101112111 |
4 | 30112001103212023 |
5 | 204121102434201 |
6 | 10031114323151 |
7 | 646312025365 |
oct | 142601234613 |
9 | 37181341474 |
10 | 13254343051 |
11 | 5691805124 |
12 | 269aa294b7 |
13 | 1332ca5151 |
14 | 8da455d35 |
15 | 528942b51 |
hex | 31605398b |
13254343051 has 2 divisors, whose sum is σ = 13254343052. Its totient is φ = 13254343050.
The previous prime is 13254343049. The next prime is 13254343087. The reversal of 13254343051 is 15034345231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13254343051 - 21 = 13254343049 is a prime.
Together with 13254343049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13254343001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627171525 + 6627171526.
It is an arithmetic number, because the mean of its divisors is an integer number (6627171526).
Almost surely, 213254343051 is an apocalyptic number.
13254343051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13254343051 is an equidigital number, since it uses as much as digits as its factorization.
13254343051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 13254343051 its reverse (15034345231), we get a palindrome (28288688282).
The spelling of 13254343051 in words is "thirteen billion, two hundred fifty-four million, three hundred forty-three thousand, fifty-one".
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