Base | Representation |
---|---|
bin | 11000101100000010… |
… | …10011100111000111 |
3 | 1021012201101101121201 |
4 | 30112001103213013 |
5 | 204121102434421 |
6 | 10031114323331 |
7 | 646312025512 |
oct | 142601234707 |
9 | 37181341551 |
10 | 13254343111 |
11 | 5691805179 |
12 | 269aa29547 |
13 | 1332ca5199 |
14 | 8da455d79 |
15 | 528942b91 |
hex | 3160539c7 |
13254343111 has 2 divisors, whose sum is σ = 13254343112. Its totient is φ = 13254343110.
The previous prime is 13254343087. The next prime is 13254343153. The reversal of 13254343111 is 11134345231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13254343111 - 221 = 13252245959 is a prime.
It is a super-2 number, since 2×132543431112 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13254343111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13254343181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627171555 + 6627171556.
It is an arithmetic number, because the mean of its divisors is an integer number (6627171556).
Almost surely, 213254343111 is an apocalyptic number.
13254343111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13254343111 is an equidigital number, since it uses as much as digits as its factorization.
13254343111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4320, while the sum is 28.
Adding to 13254343111 its reverse (11134345231), we get a palindrome (24388688342).
The spelling of 13254343111 in words is "thirteen billion, two hundred fifty-four million, three hundred forty-three thousand, one hundred eleven".
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