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1325452033113 = 31333985949567
BaseRepresentation
bin10011010010011011000…
…110001111110001011001
311200201020000211200220020
4103102123012033301121
5133204011210024423
62452523153021053
7164521636250505
oct23223306176131
94621200750806
101325452033113
114711371333aa
12194a6b254789
1397cb318cb70
144821b99d305
15247286384e3
hex1349b18fc59

1325452033113 has 8 divisors (see below), whose sum is σ = 1903213175808. Its totient is φ = 815662789584.

The previous prime is 1325452033111. The next prime is 1325452033133. The reversal of 1325452033113 is 3113302545231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1325452033113 - 21 = 1325452033111 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1325452033111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16992974745 + ... + 16992974822.

It is an arithmetic number, because the mean of its divisors is an integer number (237901646976).

Almost surely, 21325452033113 is an apocalyptic number.

1325452033113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1325452033113 is a deficient number, since it is larger than the sum of its proper divisors (577761142695).

1325452033113 is a wasteful number, since it uses less digits than its factorization.

1325452033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33985949583.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 1325452033113 its reverse (3113302545231), we get a palindrome (4438754578344).

The spelling of 1325452033113 in words is "one trillion, three hundred twenty-five billion, four hundred fifty-two million, thirty-three thousand, one hundred thirteen".

Divisors: 1 3 13 39 33985949567 101957848701 441817344371 1325452033113