132551440031 has 4 divisors (see below), whose sum is σ = 132553797432. Its totient is φ = 132549082632.

The previous prime is 132551439947. The next prime is 132551440037. The reversal of 132551440031 is 130044155231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 130044155231 = 14831 ⋅8768401.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132551440031 is a prime.

It is a super-2 number, since 2×132551440031² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132551439976 and 132551440003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132551440037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1092245 + ... + 1207518.

It is an arithmetic number, because the mean of its divisors is an integer number (33138449358).

Almost surely, 2^132551440031 is an apocalyptic number.

132551440031 is a deficient number, since it is larger than the sum of its proper divisors (2357401).

132551440031 is an equidigital number, since it uses as much as digits as its factorization.

132551440031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2357400.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 132551440031 its reverse (130044155231), we get a palindrome (262595595262).

The spelling of 132551440031 in words is "one hundred thirty-two billion, five hundred fifty-one million, four hundred forty thousand, thirty-one".