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1325534113 is a prime number
BaseRepresentation
bin100111100000010…
…0000101110100001
310102101020002222001
41033000200232201
510203314042423
6335310444001
744563565641
oct11700405641
93371202861
101325534113
11620258442
1230bb03601
13181808317
14c808a521
157b585cad
hex4f020ba1

1325534113 has 2 divisors, whose sum is σ = 1325534114. Its totient is φ = 1325534112.

The previous prime is 1325534057. The next prime is 1325534123. The reversal of 1325534113 is 3114355231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 812421009 + 513113104 = 28503^2 + 22652^2 .

It is a cyclic number.

It is not a de Polignac number, because 1325534113 - 225 = 1291979681 is a prime.

It is not a weakly prime, because it can be changed into another prime (1325534123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662767056 + 662767057.

It is an arithmetic number, because the mean of its divisors is an integer number (662767057).

Almost surely, 21325534113 is an apocalyptic number.

It is an amenable number.

1325534113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325534113 is an equidigital number, since it uses as much as digits as its factorization.

1325534113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5400, while the sum is 28.

The square root of 1325534113 is about 36407.8853134867. The cubic root of 1325534113 is about 1098.4921801128.

Adding to 1325534113 its reverse (3114355231), we get a palindrome (4439889344).

The spelling of 1325534113 in words is "one billion, three hundred twenty-five million, five hundred thirty-four thousand, one hundred thirteen".