132556027441 has 2 divisors, whose sum is σ = 132556027442. Its totient is φ = 132556027440.

The previous prime is 132556027391. The next prime is 132556027451. The reversal of 132556027441 is 144720655231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90252176400 + 42303851041 = 300420^2 + 205679^2 .

It is a cyclic number.

It is not a de Polignac number, because 132556027441 - 2⁷ = 132556027313 is a prime.

It is a super-2 number, since 2×132556027441² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132556027394 and 132556027403.

It is not a weakly prime, because it can be changed into another prime (132556027451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66278013720 + 66278013721.

It is an arithmetic number, because the mean of its divisors is an integer number (66278013721).

Almost surely, 2^132556027441 is an apocalyptic number.

It is an amenable number.

132556027441 is a deficient number, since it is larger than the sum of its proper divisors (1).

132556027441 is an equidigital number, since it uses as much as digits as its factorization.

132556027441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 40.

The spelling of 132556027441 in words is "one hundred thirty-two billion, five hundred fifty-six million, twenty-seven thousand, four hundred forty-one".