Base | Representation |
---|---|
bin | 111101101110011110… |
… | …1000111011000111011 |
3 | 110200011001112220010012 |
4 | 1323130331013120323 |
5 | 4132433320334301 |
6 | 140521223412135 |
7 | 12401601433301 |
oct | 1733475073073 |
9 | 420131486105 |
10 | 132556027451 |
11 | 51242470411 |
12 | 218348b404b |
13 | c6665bca03 |
14 | 65b6b42271 |
15 | 36ac459ebb |
hex | 1edcf4763b |
132556027451 has 2 divisors, whose sum is σ = 132556027452. Its totient is φ = 132556027450.
The previous prime is 132556027441. The next prime is 132556027493. The reversal of 132556027451 is 154720655231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132556027451 - 226 = 132488918587 is a prime.
It is a super-2 number, since 2×1325560274512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132556027399 and 132556027408.
It is not a weakly prime, because it can be changed into another prime (132556027441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66278013725 + 66278013726.
It is an arithmetic number, because the mean of its divisors is an integer number (66278013726).
Almost surely, 2132556027451 is an apocalyptic number.
132556027451 is a deficient number, since it is larger than the sum of its proper divisors (1).
132556027451 is an equidigital number, since it uses as much as digits as its factorization.
132556027451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252000, while the sum is 41.
The spelling of 132556027451 in words is "one hundred thirty-two billion, five hundred fifty-six million, twenty-seven thousand, four hundred fifty-one".
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