Base | Representation |
---|---|
bin | 10011010010100101111… |
… | …101110010011100101111 |
3 | 11200201200201221010112122 |
4 | 103102211331302130233 |
5 | 133204344344141411 |
6 | 2452553225023155 |
7 | 164526312121151 |
oct | 23224575623457 |
9 | 4621621833478 |
10 | 1325634365231 |
11 | 471220049200 |
12 | 194b00324abb |
13 | 98011b9c3a7 |
14 | 48237ca2ad1 |
15 | 247396529db |
hex | 134a5f7272f |
1325634365231 has 12 divisors (see below), whose sum is σ = 1533791830200. Its totient is φ = 1141694666640.
The previous prime is 1325634365197. The next prime is 1325634365239.
1325634365231 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 1325634365231 - 210 = 1325634364207 is a prime.
It is a super-2 number, since 2×13256343652312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1325634365239) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 288304436 + ... + 288309033.
It is an arithmetic number, because the mean of its divisors is an integer number (127815985850).
Almost surely, 21325634365231 is an apocalyptic number.
1325634365231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1325634365231 is a deficient number, since it is larger than the sum of its proper divisors (208157464969).
1325634365231 is a wasteful number, since it uses less digits than its factorization.
1325634365231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 576613510 (or 576613499 counting only the distinct ones).
The product of its digits is 1166400, while the sum is 44.
The spelling of 1325634365231 in words is "one trillion, three hundred twenty-five billion, six hundred thirty-four million, three hundred sixty-five thousand, two hundred thirty-one".
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