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1325678765231 = 4313075820801
BaseRepresentation
bin10011010010101000100…
…111001010010010101111
311200201210211110212220002
4103102220213022102233
5133204442230441411
62453001452414515
7164530361403212
oct23225047122257
94621724425802
101325678765231
11471243114617
12194b1317743b
139801b146892
144823db3d779
152473d4c333b
hex134a89ca4af

1325678765231 has 4 divisors (see below), whose sum is σ = 1328754586464. Its totient is φ = 1322602944000.

The previous prime is 1325678765171. The next prime is 1325678765273.

1325678765231 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1325678765231 is a prime.

It is a super-2 number, since 2×13256787652312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1325678765731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1537909970 + ... + 1537910831.

It is an arithmetic number, because the mean of its divisors is an integer number (332188646616).

Almost surely, 21325678765231 is an apocalyptic number.

1325678765231 is a deficient number, since it is larger than the sum of its proper divisors (3075821233).

1325678765231 is an equidigital number, since it uses as much as digits as its factorization.

1325678765231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3075821232.

The product of its digits is 12700800, while the sum is 56.

The spelling of 1325678765231 in words is "one trillion, three hundred twenty-five billion, six hundred seventy-eight million, seven hundred sixty-five thousand, two hundred thirty-one".

Divisors: 1 431 3075820801 1325678765231