Search a number
-
+
132584113 is a prime number
BaseRepresentation
bin1111110011100…
…01001010110001
3100020110222012201
413321301022301
5232420142423
621053423201
73166642414
oct771611261
9306428181
10132584113
1168927452
123849ab01
1321611a4c
1413873b7b
15b98e2ad
hex7e712b1

132584113 has 2 divisors, whose sum is σ = 132584114. Its totient is φ = 132584112.

The previous prime is 132584099. The next prime is 132584197. The reversal of 132584113 is 311485231.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131400369 + 1183744 = 11463^2 + 1088^2 .

It is an emirp because it is prime and its reverse (311485231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132584113 is a prime.

It is not a weakly prime, because it can be changed into another prime (132884113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66292056 + 66292057.

It is an arithmetic number, because the mean of its divisors is an integer number (66292057).

Almost surely, 2132584113 is an apocalyptic number.

It is an amenable number.

132584113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132584113 is an equidigital number, since it uses as much as digits as its factorization.

132584113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2880, while the sum is 28.

The square root of 132584113 is about 11514.5174888052. The cubic root of 132584113 is about 509.9142659934.

It can be divided in two parts, 13258 and 4113, that added together give a palindrome (17371).

The spelling of 132584113 in words is "one hundred thirty-two million, five hundred eighty-four thousand, one hundred thirteen".