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13260127 is a prime number
BaseRepresentation
bin110010100101…
…010101011111
3220221200110211
4302211111133
511343311002
61152113251
7220465156
oct62452537
926850424
1013260127
117537591
124535827
13299373a
141a9259d
15126ddd7
hexca555f

13260127 has 2 divisors, whose sum is σ = 13260128. Its totient is φ = 13260126.

The previous prime is 13260113. The next prime is 13260133. The reversal of 13260127 is 72106231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13260127 - 27 = 13259999 is a prime.

It is a super-2 number, since 2×132601272 = 351661936112258, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13260098 and 13260107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13260227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6630063 + 6630064.

It is an arithmetic number, because the mean of its divisors is an integer number (6630064).

Almost surely, 213260127 is an apocalyptic number.

13260127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13260127 is an equidigital number, since it uses as much as digits as its factorization.

13260127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 22.

The square root of 13260127 is about 3641.4457293773. The cubic root of 13260127 is about 236.6914450902.

Adding to 13260127 its reverse (72106231), we get a palindrome (85366358).

The spelling of 13260127 in words is "thirteen million, two hundred sixty thousand, one hundred twenty-seven".