132603131255153 has 4 divisors (see below), whose sum is σ = 142803372120948. Its totient is φ = 122402890389360.

The previous prime is 132603131255129. The next prime is 132603131255173. The reversal of 132603131255153 is 351552131306231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8496245588224 + 124106885666929 = 2914832^2 + 11140327^2 .

It is a cyclic number.

It is not a de Polignac number, because 132603131255153 - 2¹⁰ = 132603131254129 is a prime.

It is a super-3 number, since 3×132603131255153³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132603131255153.

It is not an unprimeable number, because it can be changed into a prime (132603131255173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5100120432878 + ... + 5100120432903.

It is an arithmetic number, because the mean of its divisors is an integer number (35700843030237).

Almost surely, 2^{132603131255153} is an apocalyptic number.

132603131255153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

132603131255153 is a deficient number, since it is larger than the sum of its proper divisors (10200240865795).

132603131255153 is a wasteful number, since it uses less digits than its factorization.

132603131255153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10200240865794.

The product of its (nonzero) digits is 243000, while the sum is 41.

The spelling of 132603131255153 in words is "one hundred thirty-two trillion, six hundred three billion, one hundred thirty-one million, two hundred fifty-five thousand, one hundred fifty-three".