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13260401317 = 63103210139
BaseRepresentation
bin11000101100110000…
…11010101010100101
31021020010210011220201
430112120122222211
5204124130320232
610031452230501
7646414360102
oct142630325245
937203704821
1013260401317
115695172859
1226a0a6b431
131334316817
148db191aa9
1552923cbe7
hex31661aaa5

13260401317 has 4 divisors (see below), whose sum is σ = 13260674560. Its totient is φ = 13260128076.

The previous prime is 13260401267. The next prime is 13260401333. The reversal of 13260401317 is 71310406231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 71310406231 = 143949555529.

It is a cyclic number.

It is not a de Polignac number, because 13260401317 - 227 = 13126183589 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13260401377) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41967 + ... + 168172.

It is an arithmetic number, because the mean of its divisors is an integer number (3315168640).

Almost surely, 213260401317 is an apocalyptic number.

It is an amenable number.

13260401317 is a deficient number, since it is larger than the sum of its proper divisors (273243).

13260401317 is an equidigital number, since it uses as much as digits as its factorization.

13260401317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 273242.

The product of its (nonzero) digits is 3024, while the sum is 28.

Adding to 13260401317 its reverse (71310406231), we get a palindrome (84570807548).

The spelling of 13260401317 in words is "thirteen billion, two hundred sixty million, four hundred one thousand, three hundred seventeen".

Divisors: 1 63103 210139 13260401317