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132625013197 is a prime number
BaseRepresentation
bin111101110000100010…
…0010001100111001101
3110200022212100201202211
41323201010101213031
54133104000410242
6140532130150421
712403400004025
oct1734104214715
9420285321684
10132625013197
11512783a9426
1221853a22411
13c677994991
1465c1d7ca85
1536b3535317
hex1ee11119cd

132625013197 has 2 divisors, whose sum is σ = 132625013198. Its totient is φ = 132625013196.

The previous prime is 132625013173. The next prime is 132625013201. The reversal of 132625013197 is 791310526231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78742533321 + 53882479876 = 280611^2 + 232126^2 .

It is an emirp because it is prime and its reverse (791310526231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132625013197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132625013107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66312506598 + 66312506599.

It is an arithmetic number, because the mean of its divisors is an integer number (66312506599).

Almost surely, 2132625013197 is an apocalyptic number.

It is an amenable number.

132625013197 is a deficient number, since it is larger than the sum of its proper divisors (1).

132625013197 is an equidigital number, since it uses as much as digits as its factorization.

132625013197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 40.

The spelling of 132625013197 in words is "one hundred thirty-two billion, six hundred twenty-five million, thirteen thousand, one hundred ninety-seven".