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13263225113 = 47282196279
BaseRepresentation
bin11000101101000110…
…01100000100011001
31021020100002122102202
430112203030010121
5204130341200423
610032032535545
7646450360535
oct142643140431
937210078382
1013263225113
115696821376
1226a19b15b5
131334a94bc8
148db6c8bc5
155295e9728
hex3168cc119

13263225113 has 4 divisors (see below), whose sum is σ = 13545421440. Its totient is φ = 12981028788.

The previous prime is 13263225043. The next prime is 13263225127. The reversal of 13263225113 is 31152236231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31152236231 = 241129262391.

It is a cyclic number.

It is not a de Polignac number, because 13263225113 - 210 = 13263224089 is a prime.

It is a super-2 number, since 2×132632251132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13263225133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141098093 + ... + 141098186.

It is an arithmetic number, because the mean of its divisors is an integer number (3386355360).

Almost surely, 213263225113 is an apocalyptic number.

It is an amenable number.

13263225113 is a deficient number, since it is larger than the sum of its proper divisors (282196327).

13263225113 is an equidigital number, since it uses as much as digits as its factorization.

13263225113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 282196326.

The product of its digits is 6480, while the sum is 29.

The spelling of 13263225113 in words is "thirteen billion, two hundred sixty-three million, two hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 47 282196279 13263225113