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13264300145531 is a prime number
BaseRepresentation
bin1100000100000101010111…
…1001011111101101111011
31201222001110212212001020102
43001001111321133231323
53214310241314124111
644113311345550015
72536212502643501
oct301012571375573
951861425761212
1013264300145531
1142543a36a5a36
1215a286334530b
13752a835a5286
1433bdd1b20671
1518007cb2113b
hexc1055e5fb7b

13264300145531 has 2 divisors, whose sum is σ = 13264300145532. Its totient is φ = 13264300145530.

The previous prime is 13264300145521. The next prime is 13264300145533. The reversal of 13264300145531 is 13554100346231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13264300145531 - 210 = 13264300144507 is a prime.

It is a super-2 number, since 2×132643001455312 (a number of 27 digits) contains 22 as substring.

Together with 13264300145533, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13264300145533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6632150072765 + 6632150072766.

It is an arithmetic number, because the mean of its divisors is an integer number (6632150072766).

Almost surely, 213264300145531 is an apocalyptic number.

13264300145531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13264300145531 is an equidigital number, since it uses as much as digits as its factorization.

13264300145531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 38.

The spelling of 13264300145531 in words is "thirteen trillion, two hundred sixty-four billion, three hundred million, one hundred forty-five thousand, five hundred thirty-one".