Base | Representation |
---|---|
bin | 11110001010010111001101… |
… | …100010000101101111001011 |
3 | 122101200112220102020112212002 |
4 | 132022113031202011233023 |
5 | 114341343343334441020 |
6 | 1150044103242541215 |
7 | 36640620501605555 |
oct | 3612271542055713 |
9 | 571615812215762 |
10 | 132653513202635 |
11 | 392a4047a29807 |
12 | 12a6518120780b |
13 | 59032323265a9 |
14 | 24a867005a4d5 |
15 | 1050950402975 |
hex | 78a5cd885bcb |
132653513202635 has 4 divisors (see below), whose sum is σ = 159184215843168. Its totient is φ = 106122810562104.
The previous prime is 132653513202619. The next prime is 132653513202659. The reversal of 132653513202635 is 536202315356231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132653513202635 - 24 = 132653513202619 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 132653513202635.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13265351320259 + ... + 13265351320268.
It is an arithmetic number, because the mean of its divisors is an integer number (39796053960792).
Almost surely, 2132653513202635 is an apocalyptic number.
132653513202635 is a deficient number, since it is larger than the sum of its proper divisors (26530702640533).
132653513202635 is an equidigital number, since it uses as much as digits as its factorization.
132653513202635 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26530702640532.
The product of its (nonzero) digits is 2916000, while the sum is 47.
Adding to 132653513202635 its reverse (536202315356231), we get a palindrome (668855828558866).
The spelling of 132653513202635 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred thirteen million, two hundred two thousand, six hundred thirty-five".
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