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132653564630473 is a prime number
BaseRepresentation
bin11110001010010111010000…
…100110010001010111001001
3122101200120001000000100120211
4132022113100212101113021
5114341344000021133343
61150044112321121121
736640621665001135
oct3612272046212711
9571616030010524
10132653564630473
11392a4073a65257
1212a651964891a1
13590323cb91873
1424a8676c063c5
151050954bb079d
hex78a5d09915c9

132653564630473 has 2 divisors, whose sum is σ = 132653564630474. Its totient is φ = 132653564630472.

The previous prime is 132653564630399. The next prime is 132653564630497. The reversal of 132653564630473 is 374036465356231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132276750352569 + 376814277904 = 11501163^2 + 613852^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132653564630473 is a prime.

It is a super-3 number, since 3×1326535646304733 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (132650564630473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326782315236 + 66326782315237.

It is an arithmetic number, because the mean of its divisors is an integer number (66326782315237).

Almost surely, 2132653564630473 is an apocalyptic number.

It is an amenable number.

132653564630473 is a deficient number, since it is larger than the sum of its proper divisors (1).

132653564630473 is an equidigital number, since it uses as much as digits as its factorization.

132653564630473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97977600, while the sum is 58.

The spelling of 132653564630473 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred sixty-four million, six hundred thirty thousand, four hundred seventy-three".