Base | Representation |
---|---|
bin | 11110001010010111010110… |
… | …011110101011101011000111 |
3 | 122101200120021212200111202101 |
4 | 132022113112132223223013 |
5 | 114341344200301220031 |
6 | 1150044130204052531 |
7 | 36640624303501165 |
oct | 3612272636535307 |
9 | 571616255614671 |
10 | 132653663304391 |
11 | 392a4114730449 |
12 | 12a65203534147 |
13 | 590325745c8b8 |
14 | 24a8685d70235 |
15 | 105095d6a2361 |
hex | 78a5d67abac7 |
132653663304391 has 2 divisors, whose sum is σ = 132653663304392. Its totient is φ = 132653663304390.
The previous prime is 132653663304353. The next prime is 132653663304493. The reversal of 132653663304391 is 193403366356231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132653663304391 - 213 = 132653663296199 is a prime.
It is a super-2 number, since 2×1326536633043912 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132653663304341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326831652195 + 66326831652196.
It is an arithmetic number, because the mean of its divisors is an integer number (66326831652196).
Almost surely, 2132653663304391 is an apocalyptic number.
132653663304391 is a deficient number, since it is larger than the sum of its proper divisors (1).
132653663304391 is an equidigital number, since it uses as much as digits as its factorization.
132653663304391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18895680, while the sum is 55.
The spelling of 132653663304391 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, six hundred sixty-three million, three hundred four thousand, three hundred ninety-one".
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