Base | Representation |
---|---|
bin | 1100000100001010010101… |
… | …0110011100000111111010 |
3 | 1201222011220210002211100112 |
4 | 3001002211112130013322 |
5 | 3214321004040224200 |
6 | 44114051524304322 |
7 | 2536260520104464 |
oct | 301024526340772 |
9 | 51864823084315 |
10 | 13265633133050 |
11 | 4254a18084211 |
12 | 15a2b758420a2 |
13 | 752c367bcc9c |
14 | 33c0bab8b134 |
15 | 180109b7a535 |
hex | c10a559c1fa |
13265633133050 has 24 divisors (see below), whose sum is σ = 24825452352096. Its totient is φ = 5273699549040.
The previous prime is 13265633133023. The next prime is 13265633133119. The reversal of 13265633133050 is 5033133656231.
It is a super-3 number, since 3×132656331330503 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13265633132989 and 13265633133007.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 813834374 + ... + 813850673.
It is an arithmetic number, because the mean of its divisors is an integer number (1034393848004).
Almost surely, 213265633133050 is an apocalyptic number.
13265633133050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13265633133050 is a deficient number, since it is larger than the sum of its proper divisors (11559819219046).
13265633133050 is a wasteful number, since it uses less digits than its factorization.
13265633133050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1627685222 (or 1627685217 counting only the distinct ones).
The product of its (nonzero) digits is 437400, while the sum is 41.
Adding to 13265633133050 its reverse (5033133656231), we get a palindrome (18298766789281).
The spelling of 13265633133050 in words is "thirteen trillion, two hundred sixty-five billion, six hundred thirty-three million, one hundred thirty-three thousand, fifty".
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