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132711664273 is a prime number
BaseRepresentation
bin111101110011000111…
…0110100101010010001
3110200112220102001200221
41323212032310222101
54133243141224043
6140544503313041
712405501351046
oct1734616645221
9420486361627
10132711664273
1151312302691
1221878a4b781
13c68c9134c6
1465cd6971cd
1536bae4e8ed
hex1ee63b4a91

132711664273 has 2 divisors, whose sum is σ = 132711664274. Its totient is φ = 132711664272.

The previous prime is 132711664271. The next prime is 132711664307. The reversal of 132711664273 is 372466117231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125956139409 + 6755524864 = 354903^2 + 82192^2 .

It is a cyclic number.

It is not a de Polignac number, because 132711664273 - 21 = 132711664271 is a prime.

It is a super-2 number, since 2×1327116642732 (a number of 23 digits) contains 22 as substring.

Together with 132711664271, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (132711664271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66355832136 + 66355832137.

It is an arithmetic number, because the mean of its divisors is an integer number (66355832137).

Almost surely, 2132711664273 is an apocalyptic number.

It is an amenable number.

132711664273 is a deficient number, since it is larger than the sum of its proper divisors (1).

132711664273 is an equidigital number, since it uses as much as digits as its factorization.

132711664273 is an evil number, because the sum of its binary digits is even.

The product of its digits is 254016, while the sum is 43.

The spelling of 132711664273 in words is "one hundred thirty-two billion, seven hundred eleven million, six hundred sixty-four thousand, two hundred seventy-three".