Base | Representation |
---|---|
bin | 11110001011100101011010… |
… | …100101010110110011111111 |
3 | 122101222120122111011022020021 |
4 | 132023211122211112303333 |
5 | 114344232331402300322 |
6 | 1150150431445033011 |
7 | 36646652411042164 |
oct | 3613453245266377 |
9 | 571876574138207 |
10 | 132737484025087 |
11 | 39326718300537 |
12 | 12a794b69b5767 |
13 | 590b125005296 |
14 | 24ac75831206b |
15 | 1052c172d14c7 |
hex | 78b95a956cff |
132737484025087 has 2 divisors, whose sum is σ = 132737484025088. Its totient is φ = 132737484025086.
The previous prime is 132737484025021. The next prime is 132737484025093. The reversal of 132737484025087 is 780520484737231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132737484025087 - 219 = 132737483500799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132737484035087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66368742012543 + 66368742012544.
It is an arithmetic number, because the mean of its divisors is an integer number (66368742012544).
Almost surely, 2132737484025087 is an apocalyptic number.
132737484025087 is a deficient number, since it is larger than the sum of its proper divisors (1).
132737484025087 is an equidigital number, since it uses as much as digits as its factorization.
132737484025087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63221760, while the sum is 61.
The spelling of 132737484025087 in words is "one hundred thirty-two trillion, seven hundred thirty-seven billion, four hundred eighty-four million, twenty-five thousand, eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •