Base | Representation |
---|---|
bin | 11110001011101000000111… |
… | …011010110110111011001111 |
3 | 122101222212010120110122111122 |
4 | 132023220013122312323033 |
5 | 114344304301213401112 |
6 | 1150152031311511155 |
7 | 36650114311120364 |
oct | 3613500732667317 |
9 | 571885116418448 |
10 | 132740383731407 |
11 | 39327976099841 |
12 | 12a79b85b284bb |
13 | 590b4979a243a |
14 | 24ac95148c46b |
15 | 1052d36b63872 |
hex | 78ba076b6ecf |
132740383731407 has 4 divisors (see below), whose sum is σ = 132740691346896. Its totient is φ = 132740076115920.
The previous prime is 132740383731391. The next prime is 132740383731457. The reversal of 132740383731407 is 704137383047231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132740383731407 - 24 = 132740383731391 is a prime.
It is a super-2 number, since 2×1327403837314072 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132740383731457) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153159563 + ... + 154023804.
It is an arithmetic number, because the mean of its divisors is an integer number (33185172836724).
Almost surely, 2132740383731407 is an apocalyptic number.
132740383731407 is a deficient number, since it is larger than the sum of its proper divisors (307615489).
132740383731407 is an equidigital number, since it uses as much as digits as its factorization.
132740383731407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 307615488.
The product of its (nonzero) digits is 7112448, while the sum is 53.
The spelling of 132740383731407 in words is "one hundred thirty-two trillion, seven hundred forty billion, three hundred eighty-three million, seven hundred thirty-one thousand, four hundred seven".
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