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132740383731407 = 432121307183367
BaseRepresentation
bin11110001011101000000111…
…011010110110111011001111
3122101222212010120110122111122
4132023220013122312323033
5114344304301213401112
61150152031311511155
736650114311120364
oct3613500732667317
9571885116418448
10132740383731407
1139327976099841
1212a79b85b284bb
13590b4979a243a
1424ac95148c46b
151052d36b63872
hex78ba076b6ecf

132740383731407 has 4 divisors (see below), whose sum is σ = 132740691346896. Its totient is φ = 132740076115920.

The previous prime is 132740383731391. The next prime is 132740383731457. The reversal of 132740383731407 is 704137383047231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132740383731407 - 24 = 132740383731391 is a prime.

It is a super-2 number, since 2×1327403837314072 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132740383731457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153159563 + ... + 154023804.

It is an arithmetic number, because the mean of its divisors is an integer number (33185172836724).

Almost surely, 2132740383731407 is an apocalyptic number.

132740383731407 is a deficient number, since it is larger than the sum of its proper divisors (307615489).

132740383731407 is an equidigital number, since it uses as much as digits as its factorization.

132740383731407 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 307615488.

The product of its (nonzero) digits is 7112448, while the sum is 53.

The spelling of 132740383731407 in words is "one hundred thirty-two trillion, seven hundred forty billion, three hundred eighty-three million, seven hundred thirty-one thousand, four hundred seven".

Divisors: 1 432121 307183367 132740383731407