Base | Representation |
---|---|
bin | 10011010100110100010… |
… | …101101001011010011011 |
3 | 11200221212012112112222022 |
4 | 103110310111221122123 |
5 | 133224242340444342 |
6 | 2454030233245055 |
7 | 164642435054243 |
oct | 23246425513233 |
9 | 4627765475868 |
10 | 1328022984347 |
11 | 472236398094 |
12 | 19546826378b |
13 | 98302a01a97 |
14 | 483c31dcb23 |
15 | 248291cb9d2 |
hex | 1353456969b |
1328022984347 has 2 divisors, whose sum is σ = 1328022984348. Its totient is φ = 1328022984346.
The previous prime is 1328022984263. The next prime is 1328022984349. The reversal of 1328022984347 is 7434892208231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1328022984347 - 28 = 1328022984091 is a prime.
Together with 1328022984349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1328022984349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 664011492173 + 664011492174.
It is an arithmetic number, because the mean of its divisors is an integer number (664011492174).
Almost surely, 21328022984347 is an apocalyptic number.
1328022984347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1328022984347 is an equidigital number, since it uses as much as digits as its factorization.
1328022984347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4644864, while the sum is 53.
The spelling of 1328022984347 in words is "one trillion, three hundred twenty-eight billion, twenty-two million, nine hundred eighty-four thousand, three hundred forty-seven".
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